Materials and Methods: Experiment #1: Before we did anything we punched fifteen discs out of the filter paper. Once we had our discs we then got our catalane, potato juice. We put it into small containers with lids with labels on them that read 100%, 80%, 60%, 40%, 20% and 0%. Each container contained water and potato juice. In the 100% it contained ml of catalane and Mol of water. In the 80% it contained ml of catalane and ml of water. In the 60% it contained ml of catalane and ml of water. In the 40% it contained ml of catalane and ml of water.
In the it contained ml of catalane and ml of water. Lastly, in the 0% it contained ml of catalane and ml of water. Once we had our catalane ready we poured hydrogen peroxide in a graduated cylinder to the top. We got our timer ready and then we began our experiment. First we did the 0% catalane. We grabbed the edge of one of the filter paper discs and dipped it into the 0% catalane and then dropped it into the graduated cylinder containing the hydrogen peroxide. For the 0% catalane you had to wait three minutes because the disc would not go to the top. We then moved on the do the 20% catalane.
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We dipped the filter paper disc into the catalane and then blotted it so there was no dripping of the catalane. We then roped it into the hydrogen peroxide and timed it until it reached the top of the graduated cylinder. We repeated this step three times for each of the catalysts. Once we had the times of all three trials you then calculated the average time. Once you had the average time you divided the distance in millimeters by the average time and that is what gave you your reaction rate. Experiment #2: First, before you do anything, you had to heat up the hydrogen peroxide to 80*C.
You then used the same labeled containers with the catalane in it from experiment one. For our experiment we did our first trial at 70*C because our hydrogen peroxide dropped 10* before we could perform the experiment. First we dipped our filter disc into the 100% catalane and blotted it until there was no excess catalane on the disc and then we dropped it in the peroxide at 70*C. We timed how long it took to come up, but because the temperature is so hot you are just going to have to wait the three minutes again because it will not float up to the top.
We then cooled our hydrogen peroxide down in the tub of ice to 50*C and dipped our filter paper disc into the 100% catalane, blotted it, and then dropped it into the hydrogen peroxide. We timed how long it took to reach the top as well. We then repeated this step for 40*C, 30*C and 20*C. Once we recorded the time and the distance for each one you then calculated the reaction time by dividing the time by the distance. IV. Results: % Catalane Time 3-friars (Sec. ) Average Time (Sec. ) Distance (mm) Reaction Rate (mm/sec) 100 47 As ass 45. As 44. As mm 2. Mm/s 80 56. S 48. Is ass 52. AS 2. Mm/s 60 ass 59. 75 ASS 56. AS 2. Mm/s ASS sass 104. As 98. AS 1. Mm/s 20 97. As 128. 85 SASS 110. As 1. Mm/s SASS sass Mom Mom/s Graph By the graph shown above the results we obtained from experiment one tell us hat the more enzyme concentration that is present the faster the reaction rate will be. This graph also supports my hypothesis because my hypothesis stated that I think the reaction would happen faster, and in fact it did happen at a faster rate. Experiment 2: Data Table Temperature (*C) Time (sec) Reaction Rate (m’s) 70*C 50*C 90. S mm 1. Mm/s 40*C 42. As 30*C 61. As 1. Mm/s 20*C 127. As 0. Mm/s Based on the graph above I can conclude from this experiment that the effect of temperature on the reaction rate is that the longer it takes the disc to rise causes a lower reaction because the enzyme proteins begin to denature. The graph above also showed some support for my hypothesis. I predicted that the filter discs would float sooner in a warmer substrate but once I looked at my graph above the reaction rate did get faster but when the temperature went up the filter discs didn’t float at all.
V. Discussion: The results for my experiment #1 supported my hypothesis. My hypothesis stated I think that the filter paper discs would float sooner when you add more enzymes, and when I plotted my line graph of my data it showed me that over time the reaction rate sped up when there were more enzymes present. The ERM 100% enzyme is relative only to the amount of enzyme our professor mixed, meaning that the enzyme concentration could have been a lot higher.
I think that the trend of the graph would continue if the enzyme samples got even more concentrated than the ones in this lab because the graph showed us with more enzymes present the faster the reaction will be. If you were to set up a lab to test the effect of varying substrate concentration the student would first have to punch out the three holes of filter disc paper, just like we did, and put the hydrogen peroxide in a graduated cylinder. The student would then have to first oak the filter paper in the catalane until the filter paper was completely covered, then blot it on a paper towel to make sure there isn’t any excess catalane.
Then place the filter paper into the hydrogen peroxide and time how long it takes to reach the top of the cylinder. Once done calculate your reaction rate then repeat two more times for a more accurate reading. The results for my experiment #2 showed some support for my hypothesis. I predicted that the filter discs would float sooner in the warmer substrate, but when I plotted my graph it showed me that yes, when I heated up the substrate he reaction rate did get faster, but when the temperature got too hot the filter discs did not float at all.
They did not float at all because if the enzymes are heated up to much it causes the enzymes bonds to break which would not allow them to bond to the substrate, causing the discs not to float. If you mixed up the enzyme solution and the substrate solution will cause the discs not to float because mixing them takes heat and energy away causing the reaction rate to go down. Also if you let an enzyme boil the heat breaks down the bonds that make up the enzyme and it loses its shape, which leads it to not being allowed to bond o the substrate.